Asian Journal of Mathematics

Volume 17 (2013)

Number 4

Noether’s problem and unramified Brauer groups

Pages: 689 – 714

DOI: https://dx.doi.org/10.4310/AJM.2013.v17.n4.a8

Authors

Akinari Hoshi (Department of Mathematics, Rikkyo University, Tokyo, Japan)

Ming-Chang Kang (Department of Mathematics and Taida Institute of Mathematical Sciences, National Taiwan University, Taipei, Taiwan)

Boris E. Kunyavskii (Department of Mathematics, Bar-Ilan University, Ramat Gan, Israel)

Abstract

Let $k$ be any field, $G$ be a finite group acting on the rational function field $k(x_g : g \in G)$ by $h \cdot x_g = x_{hg}$ for any $h, g \in G$. Define $k(G) = k(x_g : g \in G)^G$. Noether’s problem asks whether $k(G)$ is rational (= purely transcendental) over $k$. It is known that, if $\mathbb{C}(G)$ is rational over $\mathbb{C}$, then $B_0(G) = 0$ where $B_0(G)$ is the unramified Brauer group of $\mathbb{C}(G)$ over $\mathbb{C}$. Bogomolov showed that, if $G$ is a $p$-group of order $p^5$, then $B_0(G) = 0$. This result was disproved by Moravec for $p = 3, 5, 7$ by computer calculations. We will prove the following theorem. Theorem. Let $p$ be any odd prime number, $G$ be a group of order $p^5$. Then $B_0(G) \neq 0$ if and only if $G$ belongs to the isoclinism family ${\Phi}_{10}$ in R. James’s classification of groups of order $p^5$.

Keywords

Noether’s problem, rationality problem, unramified Brauer groups, Bogomolov multipliers, rationality, retract rationality

2010 Mathematics Subject Classification

12F12, 13A50, 14E08, 14M20, 20J06

Published 27 December 2013